СРОЧНО буду очень благодарен если за 5 мин
2 Ответ (-а, -ов)
_x-1_ + _x+1_ = _(x-1)·(x-1)+(x+1)(x+1)_ = _x²-x-x+1+x²+x+x+1_ =
x+1 x-1 (x+1)(x-1) (x+1)(x-1)
= _ 2x²+2_= _2·(x+1)_ = _2_
(x+1)(x-1) (x+1)(x-1) x-1.
x+1 x-1 (x+1)(x-1) (x+1)(x-1)
= _ 2x²+2_= _2·(x+1)_ = _2_
(x+1)(x-1) (x+1)(x-1) x-1.
( ( x — 1 )/( x + 1 )) + (( x + 1 )/( x — 1 )) = ( ( x — 1 )^2 + ( x + 1 )^2 ) / ( x^2 — 1 ) = ( x^2 — 2x + 1 + x^2 + 2x + 1 ) / ( x^2 — 1 ) = ( 2x^2 + 2 ) / ( x^2 — 1 )