Решите 5log⅓ 81-(log2 1/16)²
1 Ответ (-а, -ов)
Log1/3 81= -4
log2 1/16= -4
5*(-4) -(-4)^2=
-20 -16= -36
log2 1/16= -4
5*(-4) -(-4)^2=
-20 -16= -36