Номер 109 (1 и 4 ) пожалуйста
1 Ответ (-а, -ов)
108.1![\sqrt[3]{(7- \sqrt{22} )(7+ \sqrt{22}) } = \sqrt[3]{49-22} = \sqrt[3]{27} =3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%287-%20%5Csqrt%7B22%7D%20%29%287%2B%20%5Csqrt%7B22%7D%29%20%7D%20%3D%20%5Csqrt%5B3%5D%7B49-22%7D%20%3D%20%5Csqrt%5B3%5D%7B27%7D%20%3D3 "\sqrt[3]{(7- \sqrt{22} )(7+ \sqrt{22}) } = \sqrt[3]{49-22} = \sqrt[3]{27} =3")
108.2
1/(4+2√3)+1/(4-2√3)=(4-2√3+4+2√3)/(16-12)=8/4=2
109.1
2*√(3/2*2/3)-6√(3/8*2/3)+8√(3/2*2/3)=2√1-6√1/4+8√1=2+6/2-8=10-3=7
109.4
![\sqrt[4]{125/27*5/3} - \sqrt[4]{375*5/3} - \sqrt[4]{1/135*5/3} =](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B125%2F27%2A5%2F3%7D%20-%20%5Csqrt%5B4%5D%7B375%2A5%2F3%7D%20-%20%5Csqrt%5B4%5D%7B1%2F135%2A5%2F3%7D%20%3D "\sqrt[4]{125/27*5/3} - \sqrt[4]{375*5/3} - \sqrt[4]{1/135*5/3} =")
![\sqrt[4]{625/81} - \sqrt[4]{625} - \sqrt[4]{1/81} =5/3-5-1/3=4/3-5=-11/3](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B625%2F81%7D%20-%20%5Csqrt%5B4%5D%7B625%7D%20-%20%5Csqrt%5B4%5D%7B1%2F81%7D%20%3D5%2F3-5-1%2F3%3D4%2F3-5%3D-11%2F3 "\sqrt[4]{625/81} - \sqrt[4]{625} - \sqrt[4]{1/81} =5/3-5-1/3=4/3-5=-11/3")
108.2
1/(4+2√3)+1/(4-2√3)=(4-2√3+4+2√3)/(16-12)=8/4=2
109.1
2*√(3/2*2/3)-6√(3/8*2/3)+8√(3/2*2/3)=2√1-6√1/4+8√1=2+6/2-8=10-3=7
109.4